Trig Functions — Question 6

Question 6 - Solution

(a) Use sum-to-product identities:

We apply: $$\sin A + \sin B = 2 \sin\left( \frac{A + B}{2} \right) \cos\left( \frac{A - B}{2} \right)$$

Let $A = 3x$, $B = x$: $$f(x) = \sin(x) + \sin(3x) = 2 \sin\left( \frac{3x + x}{2} \right) \cos\left( \frac{3x - x}{2} \right) = 2 \sin(2x) \cos(x)$$

$$\boxed{f(x) = 2 \sin(2x) \cos(x)}$$

(b) Solve $f(x) = 0$ on $[0, 2\pi]$:

$$2 \sin(2x) \cos(x) = 0 \Rightarrow \sin(2x) = 0 \quad \text{or} \quad \cos(x) = 0$$

Solve $\sin(2x) = 0$: $$2x = n\pi \Rightarrow x = \frac{n\pi}{2} \Rightarrow x = 0,\ \frac{\pi}{2},\ \pi,\ \frac{3\pi}{2},\ 2\pi$$

Solve $\cos(x) = 0$: $$x = \frac{\pi}{2},\ \frac{3\pi}{2}$$

Union of solutions:

$$\boxed{x = 0,\ \frac{\pi}{2},\ \pi,\ \frac{3\pi}{2},\ 2\pi}$$

(c) Sketch the graph of $f(x) = \sin(x) + \sin(3x)$

The graph is periodic with the least common multiple of the periods of $\sin(x)$ and $\sin(3x)$.

Period of $\sin(x)$: $2\pi$ Period of $\sin(3x)$: $\frac{2\pi}{3}$ LCM of $2\pi$ and $\frac{2\pi}{3}$ is $2\pi$

So sketch one full period over $[0, 2\pi]$. Use the product form $f(x) = 2 \sin(2x)\cos(x)$ to help identify:

Zeros: Where either $\sin(2x) = 0$ or $\cos(x) = 0$ Amplitude varies due to the product of two trig functions Important points: $x = 0, \frac{\pi}{2}, \pi, \frac{3\pi}{2}, 2\pi$, and midpoints between for peaks/troughs