Solving Trig Equations with Calculators, Part II — Question 4

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Question 4

Solve the equation cos⁡(3x)=0.2\cos(3x) = 0.2 for all x∈[0,2π]x \in [0, 2\pi], and round your answers to two decimal places.

Original worksheet page 1: question and worked solution for 1-6-004
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Question 4 - Solution

Step 1: Isolate the trigonometric function. The equation becomes

cos⁡(3x)=0.2,u=3x,0≤u≤6π.\cos(3x)=0.2,\qquad u=3x,\qquad 0\le u\le 6\pi.

Let α=arccos⁡(0.2)\alpha=\arccos(0.2). All solutions are

u=±α+2kπ,k∈ℤ.u=\pm\alpha+2k\pi,\qquad k\in\mathbb Z.

Step 2: Restrict and convert. Keep precisely the values of uu in [0,6π][0,6\pi] and divide by 33.

Evaluating the inverse function at full precision and rounding only the final values gives

x≈0.46,1.64,2.55,3.73,4.65,5.83.\boxed{x\approx 0.46,\ 1.64,\ 2.55,\ 3.73,\ 4.65,\ 5.83}.

These are all 6 solutions in the stated interval, in radians. Substitution of the unrounded values verifies the original equation.

Original worksheet page 2: question and worked solution for 1-6-004

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