Infinite Limits — Question 8

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Question 8

Evaluate the limit: limx→2+1x−2\lim_{x \to 2^+} \frac{1}{x - 2}

Original worksheet page 1: question and worked solution for 2-6-008
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Question 8 - Solution

We are given the limit: limx→2+1x−2\lim_{x \to 2^+} \frac{1}{x - 2}

Step 1: Analyze the expression near x=2+x = 2^+

As xx approaches 2 from the right, the value of x−2x - 2 becomes a very small positive number. Therefore, 1x−2\frac{1}{x - 2} becomes a very large positive number.

x→2+⇒x−2→0+⇒1x−2→+∞x \to 2^+ \quad \Rightarrow \quad x - 2 \to 0^+ \quad \Rightarrow \quad \frac{1}{x - 2} \to +\infty

Conclusion: limx→2+1x−2=+∞\boxed{\lim_{x \to 2^+} \frac{1}{x - 2} = +\infty}

This indicates that the function grows without bound as xx approaches 2 from the right.

Original worksheet page 2: question and worked solution for 2-6-008

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