Linear Approximations — Question 7

Question 7 - Solution

Let $f(x) = \ln(x)$. We choose $a = 1$ since $\ln(1) = 0$ is easy to compute.

(a) Compute the derivative: $$f'(x) = \frac{1}{x}, \quad \text{so } f'(1) = 1$$

(b) Linear approximation: $$L(x) = f(a) + f'(a)(x - a) = 0 + 1(x - 1) = x - 1$$

(c) Estimate: $$L(1.05) = 1.05 - 1 = 0.05$$

Compare to actual: $$\ln(1.05) \approx 0.04879 \quad \text{(from calculator)}$$

Conclusion: $$\boxed{\ln(1.05) \approx 0.05} \quad \text{(Linear Approximation)}$$ $$\text{Actual: } \ln(1.05) \approx 0.04879 \Rightarrow \text{Very close!}$$