More Optimization — Question 1

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Question 1

A square piece of cardboard 24 inches on each side is to be made into an open-top box by cutting equal squares from each corner and folding up the sides. What size square should be cut from each corner to maximize the volume of the box?

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Original worksheet page 1: question and worked solution for 4-9-001
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Question 1 - Solution

Let xx be the length of the square cut from each corner.

After folding, the dimensions of the box will be:

Height = xx

Length and width = 24−2x24 - 2x

Volume: V(x)=x(24−2x)2V(x) = x(24 - 2x)^2

Step 1: Expand volume function

V(x)=x(576−96x+4x2)=576x−96x2+4x3V(x) = x(576 - 96x + 4x^2) = 576x - 96x^2 + 4x^3

Step 2: Find critical points

V′(x)=576−192x+12x2⇒12x2−192x+576=0⇒x2−16x+48=0⇒x=8±16⇒x=8±4V'(x) = 576 - 192x + 12x^2 \Rightarrow 12x^2 - 192x + 576 = 0 \Rightarrow x^2 - 16x + 48 = 0 \Rightarrow x = 8 \pm \sqrt{16} \Rightarrow x = 8 \pm 4

x=4orx=12x = 4 \quad \text{or} \quad x = 12

But x=12x = 12 makes 24−2x=024 - 2x = 0 → not valid

Valid critical point: x=4x = 4

Answer: Cut out squares of size 4 in\boxed{4 \text{ in}} to maximize volume

Original worksheet page 2: question and worked solution for 4-9-001

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