Substitution Rule for Indefinite Integrals — Question 1

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Question 1

Evaluate the integral ∫xe1+x21+x2dx.\int \frac{x\,e^{\sqrt{1+x^2}}}{\sqrt{1+x^2}}\,dx.

Original worksheet page 1: question and worked solution for 5-3-001
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Question 1 - Solution

Use substitution. Let u=1+x2.u=\sqrt{1+x^2}. Then u2=1+x2⇒2udu=2xdx⇒xdx=udu.u^2=1+x^2 \quad\Rightarrow\quad 2u\,du=2x\,dx \quad\Rightarrow\quad x\,dx=u\,du.

Substitute into the integral: ∫xe1+x21+x2dx=∫ueuudu=∫eudu.\int \frac{x\,e^{\sqrt{1+x^2}}}{\sqrt{1+x^2}}\,dx = \int \frac{u\,e^{u}}{u}\,du = \int e^{u}\,du.

Integrate: ∫eudu=eu.\int e^{u}\,du = e^{u}.

Substitute back: e1+x2+C\boxed{ e^{\sqrt{1+x^2}} + C }

Original worksheet page 2: question and worked solution for 5-3-001

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