Substitution Rule for Indefinite Integrals — Question 9

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Question 9

Evaluate the integral ∫cos⁡(x)xdx.\int \frac{\cos(\sqrt{x})}{\sqrt{x}}\,dx.

Original worksheet page 1: question and worked solution for 5-3-009
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Question 9 - Solution

Rewrite the integrand to reveal a derivative pattern: 2cos⁡(x)⋅ddx(x).2\cos(\sqrt{x})\cdot \frac{d}{dx}(\sqrt{x}).

Let u=x.u=\sqrt{x}. Then du=12xdx⇒dx=2xdu.du=\frac{1}{2\sqrt{x}}\,dx \quad\Rightarrow\quad dx=2\sqrt{x}\,du.

Substitute into the integral: ∫cos⁡(x)xdx=∫cos⁡(u)x⋅2xdu=2∫cos⁡udu.\int \frac{\cos(\sqrt{x})}{\sqrt{x}}\,dx = \int \frac{\cos(u)}{\sqrt{x}}\cdot 2\sqrt{x}\,du = 2\int \cos u\,du.

Integrate: 2∫cos⁡udu=2sin⁡u.2\int \cos u\,du = 2\sin u.

Substitute back: 2sin⁡(x)+C\boxed{ 2\sin(\sqrt{x}) + C }

Original worksheet page 2: question and worked solution for 5-3-009

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