Volumes of Solids of Revolution Method of Cylinders — Question 1

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Question 1

Find the volume of the solid obtained by rotating the region bounded by y=x2andy=4y=x^2 \qquad\text{and}\qquad y=4 about the yy-axis.

See the diagram in the original worksheet below.

Rotate the shaded region about the yy-axis.

Original worksheet page 1: question and worked solution for 6-4-001
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Question 1 – Solution

1. Find the intersections and choose slices.

For shells about the yy-axis, use vertical slices parallel to the axis. The curves meet where x2=4x^2=4, so x=±2x=\pm2.

2. Choose an interval that counts each shell once.

The half-region 0≤x≤20\le x\le2 generates the entire solid. The negative half generates the same shells, so do not double the volume or integrate over both halves.

3. Identify radius, height, and the shell integral.

The radius is the distance to the yy-axis; the height is top minus bottom:r(x)=x,h(x)=4−x2.r(x)=x,\qquad h(x)=4-x^2.V=2π∫02r(x)h(x)dx=2π∫02x(4−x2)dx.V=2\pi\int_0^2 r(x)h(x)\,dx=2\pi\int_0^2 x(4-x^2)\,dx.

4. Expand and integrate.

x(4−x2)=4x−x3,∫(4x−x3)dx=2x2−x44.x(4-x^2)=4x-x^3,\qquad\int(4x-x^3)\,dx=2x^2-\frac{x^4}{4}.

5. Apply the bounds and simplify.

V=2π[2x2−x44]02=2π[(8−164)−0]=2π(4)=8π.\begin{align*} V&=2\pi\left[2x^2-\frac{x^4}{4}\right]_0^2\\&=2\pi\left[\left(8-\frac{16}{4}\right)-0\right]=2\pi(4)=\boxed{8\pi}. \end{align*}

All volumes are in cubic units.

Original worksheet page 2: question and worked solution for 6-4-001

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