Question 1 Prove that limx→∞lnxx=0.\lim_{x\to\infty}\frac{\ln x}{x}=0. Show solutionHide solution+Question 1 - Solution We compare the growth rates of the numerator and denominator. For x>0x>0, both lnx\ln x and xx are differentiable. Apply L’Hôpital’s Rule to the limit limx→∞lnxx.\lim_{x\to\infty}\frac{\ln x}{x}. Differentiate the numerator and denominator: ddx(lnx)=1x,ddx(x)=1.\frac{d}{dx}(\ln x)=\frac{1}{x}, \qquad \frac{d}{dx}(x)=1. Thus, limx→∞lnxx=limx→∞1/x1=limx→∞1x.\lim_{x\to\infty}\frac{\ln x}{x} = \lim_{x\to\infty}\frac{1/x}{1} = \lim_{x\to\infty}\frac{1}{x}. From basic limits, limx→∞1x=0.\lim_{x\to\infty}\frac{1}{x}=0. Therefore, limx→∞lnxx=0.\lim_{x\to\infty}\frac{\ln x}{x}=0. 0\boxed{0}