Approximating Definite Integrals — Question 3

PDF ↗

Question 3

Use Simpson’s Rule with n=4n=4 to approximate ∫021+x3dx.\int_0^2\sqrt{1+x^3}\,dx.

Original worksheet page 1: question and worked solution for 1-10-003
Show solutionHide solution

Question 3 – Solution

Step 1: Find the width and nodes. h=2−04=0.5,xi=0,0.5,1,1.5,2.h=\frac{2-0}{4}=0.5,\qquad x_i=0,0.5,1,1.5,2. Step 2: Evaluate f(x)=1+x3f(x)=\sqrt{1+x^3}. f(0)=1,f(0.5)=1.125,f(1)=2,f(1.5)=4.375,f(2)=3.\begin{align*} f(0)&=1,& f(0.5)&=\sqrt{1.125},& f(1)&=\sqrt2,\\ f(1.5)&=\sqrt{4.375},& f(2)&=3. \end{align*} Step 3: Apply Simpson’s Rule. S4=h3[f(0)+4f(0.5)+2f(1)+4f(1.5)+f(2)]=0.53[1+41.125+22+44.375+3]≈3.23961135.\begin{align*} S_4&=\frac h3[f(0)+4f(0.5)+2f(1)+4f(1.5)+f(2)]\\ &=\frac{0.5}{3}\left[1+4\sqrt{1.125}+2\sqrt2 +4\sqrt{4.375}+3\right]\\ &\approx3.23961135. \end{align*} S4≈3.2396\boxed{S_4\approx3.2396}

Original worksheet page 2: question and worked solution for 1-10-003

Original worksheet layout. Use Enlarge or open the PDF for a closer view.