Arc Length — Question 8

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Question 8

Use two straight chords through x=0,π/2,πx=0,\pi/2,\pi to estimate the length of y=sin⁡x,0≤x≤π.y=\sin x,\qquad0\le x\le\pi. Explain why the estimate is too small.

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Original worksheet page 1: question and worked solution for 2-1-008
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Question 8 – Solution

Step 1: List the three points. (0,0),(π2,1),(π,0).(0,0),\qquad\left(\frac\pi2,1\right),\qquad(\pi,0). Step 2: Find the first chord length. d1=(π2−0)2+(1−0)2=π24+1.\begin{align*} d_1&=\sqrt{\left(\frac\pi2-0\right)^2+(1-0)^2}\\ &=\sqrt{\frac{\pi^2}{4}+1}. \end{align*} By symmetry, d2=d1d_2=d_1. Thus Lchord=2d1=2π24+1=π2+4.\begin{align*} L_{\mathrm{chord}}&=2d_1 =2\sqrt{\frac{\pi^2}{4}+1} =\sqrt{\pi^2+4}. \end{align*} Step 3: Compare with the true length. The true arc length is L=∫0π1+cos⁡2xdx.L=\int_0^\pi\sqrt{1+\cos^2x}\,dx. A curved arc between two points is longer than its straight chord. Since the sine curve is not straight on either half, Lchord=π2+4,L>Lchord\boxed{L_{\mathrm{chord}}=\sqrt{\pi^2+4},\qquad L>L_{\mathrm{chord}}}

Original worksheet page 2: question and worked solution for 2-1-008

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