Parametric Equations and Curves — Question 9

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Question 9

Problem

Can the parabola y=x2y=x^2 be traced from right to left while the parameter increases? Give a parametrization on −2≤t≤2-2\le t\le2 that does so.

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Original worksheet page 1: question and worked solution for 3-1-009
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Question 9 – Solution

See the diagram in the original worksheet below.

Solution

  1. To trace the parabola from right to left, choose the xx-coordinate so that it decreases as tt increases. A simple choice is x=−t.x=-t.

  2. The curve must satisfy y=x2y=x^2. Substituting x=−tx=-t gives y=(−t)2=t2.y=(-t)^2=t^2. Hence one suitable parametrization is x=−t,y=t2,−2≤t≤2.\boxed{x=-t,\qquad y=t^2,\qquad -2\le t\le2}.

  3. Verify that the curve is correct by eliminating the parameter: t=−x⇒y=t2=(−x)2=x2.t=-x \quad\Longrightarrow\quad y=t^2=(-x)^2=x^2.

  4. Verify the direction. At t=−2t=-2, the point is (2,4)(2,4); at t=0t=0, it is (0,0)(0,0); and at t=2t=2, it is (−2,4)(-2,4).

  5. Also, dx/dt=−1<0dx/dt=-1<0, so xx decreases continuously. Therefore, the parabola is traced from right to left as required.

Original worksheet page 2: question and worked solution for 3-1-009

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