Quadric Surfaces — Question 1

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Question 1

Put 4x2+y2+9z2−8x+6y−36z+4=04x^2+y^2+9z^2-8x+6y-36z+4=0 in standard form. Classify the surface and give its center, semiaxes, and coordinate-direction extreme points.

Original worksheet page 1: question and worked solution for 6-4-001
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Question 1 – Solution

Strategy Complete the square separately in x,y,zx,y,z, then divide by the resulting constant.

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Standard form Completing squares gives 4(x−1)2+(y+3)2+9(z−2)2=45,4(x-1)^2+(y+3)^2+9(z-2)^2=45, so (x−1)245/4+(y+3)245+(z−2)25=1.\boxed{\frac{(x-1)^2}{45/4}+\frac{(y+3)^2}{45}+\frac{(z-2)^2}{5}=1}.

Geometry This is an ellipsoid centered at (1,−3,2)\boxed{(1,-3,2)} with semiaxes 35/23\sqrt 5/2, 353\sqrt 5, and 5\sqrt 5. Its axial extreme points are (1±35/2,−3,2),(1,−3±35,2),(1,−3,2±5).(1\pm 3\sqrt 5/2,-3,2),\quad(1,-3\pm 3\sqrt 5,2),\quad(1,-3,2\pm\sqrt 5).

Verification Substitution of any listed endpoint makes exactly one normalized square equal to 1.

Original worksheet page 2: question and worked solution for 6-4-001

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