Functions of Several Variables — Question 4

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Question 4

A temperature field is T(x,y,z)=100e−(x2+y2+z2)/4.T(x,y,z)=100e^{-(x^2+y^2+z^2)/4}.

Tasks

  1. Describe the level surface T=T0T=T_0 for 0<T0≤1000<T_0\le 100.

  2. Find the 5050-degree level radius.

  3. Along (t,t,0)(t,t,0), find when the temperature first reaches 5050.

Original worksheet page 1: question and worked solution for 1-5-004
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Question 4 – Solution

Strategy Take natural logarithms after isolating the exponential.

See the diagram in the original worksheet below.

Step 1: General level From T0/100=e−r2/4T_0/100=e^{-r^2/4}, ln⁡(T0/100)=−r2/4⇒r2=4ln⁡(100/T0).\ln(T_0/100)=-r^2/4\Longrightarrow\boxed{r^2=4\ln(100/T_0)}. Thus levels are concentric spheres; T0=100T_0=100 degenerates to the origin.

Step 2: Fifty-degree surface For T0=50T_0=50, r2=4ln⁡2r^2=4\ln 2, so r=2ln⁡2\boxed{r=2\sqrt{\ln 2}}.

Step 3: Path On (t,t,0)(t,t,0), r2=2t2r^2=2t^2. Hence 2t2=4ln⁡2⇒t=±2ln⁡2.2t^2=4\ln 2\Longrightarrow t=\pm\sqrt{2\ln 2}. Starting at t=0t=0 and moving with increasing tt, the first time is t=2ln⁡2\boxed{t=\sqrt{2\ln 2}}.

Original worksheet page 2: question and worked solution for 1-5-004

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