Curl and Divergence β€” Question 3

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Question 3

Let 𝑭(x,y,z)=βŸ¨βˆ’2y,2x,z2⟩.\mathbf F(x,y,z)=\langle-2y,\,2x,\,z^2\rangle. At P=(1,βˆ’1,2)P=(1,-1,2), determine the local expansion rate and the curl vector.

Tasks

  1. Compute and evaluate the divergence.

  2. Compute and evaluate the curl.

  3. Interpret the curl’s axis, direction, and infinitesimal angular-speed relation.

Original worksheet page 1: question and worked solution for 6-1-003
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Question 3 – Solution

Strategy. Use divergence for local volume change and curl for twice the infinitesimal angular-velocity vector.

Step 1: Expansion rate βˆ‡β‹…π‘­=0+0+2z=2z.\nabla\cdot\mathbf F=0+0+2z=2z. At PP, this is (βˆ‡β‹…π‘­)(P)=4,\boxed{(\nabla\cdot\mathbf F)(P)=4}, so the field has positive local expansion there.

Step 2: Curl βˆ‡Γ—π‘­=⟨0βˆ’0,0βˆ’0,2βˆ’(βˆ’2)⟩=⟨0,0,4⟩.\nabla\times\mathbf F =\langle 0-0,0-0,2-(-2)\rangle =\boxed{\langle 0,0,4\rangle}. This curl is constant, so its value at PP is the same vector.

See the diagram in the original worksheet below.

Step 3: Interpret The curl points along the positive zz-axis, indicating counterclockwise rotation in horizontal planes when viewed from +z+z. The associated infinitesimal angular-velocity vector is half the curl: Ο‰β†’=⟨0,0,2⟩.\boxed{\vec\omega=\langle 0,0,2\rangle}.

Verification The horizontal field βŸ¨βˆ’2y,2x⟩\langle-2y,2x\rangle is rigid rotation with angular speed 22, which matches |βˆ‡Γ—π‘­|/2=2|\nabla\times\mathbf F|/2=2.

Original worksheet page 2: question and worked solution for 6-1-003

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