Parametric Surfaces β€” Question 1

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Question 1

Consider the surface patch 𝒓(u,v)=⟨u,v,1+2uβˆ’v⟩,0≀u≀2,0≀v≀1.\mathbf r(u,v)=\langle u,v,1+2u-v\rangle, \qquad 0\le u\le 2,\qquad 0\le v\le 1.

Tasks

  1. Identify the surface and its parameter-domain image.

  2. Find two tangent vectors and a normal vector.

  3. List the four corner points of the patch.

Original worksheet page 1: question and worked solution for 6-2-001
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Question 1 – Solution

Strategy. Read x=ux=u and y=vy=v, eliminate the parameters, and map the rectangle’s four corners.

Step 1: Identify the surface Since x=ux=u and y=vy=v, z=1+2xβˆ’y.z=1+2x-y. Thus the image is the portion of this plane above the rectangle 0≀x≀20\le x\le 2, 0≀y≀10\le y\le 1.

Step 2: Tangent and normal vectors 𝒓u=⟨1,0,2⟩,𝒓v=⟨0,1,βˆ’1⟩.\mathbf r_u=\langle 1,0,2\rangle, \qquad \mathbf r_v=\langle 0,1,-1\rangle. Therefore 𝒓u×𝒓v=βŸ¨βˆ’2,1,1⟩.\boxed{\mathbf r_u\times\mathbf r_v=\langle-2,1,1\rangle}.

See the diagram in the original worksheet below.

Step 3: Map the corners 𝒓(0,0)=(0,0,1),𝒓(2,0)=(2,0,5),𝒓(0,1)=(0,1,0),𝒓(2,1)=(2,1,4).\begin{align*} \mathbf r(0,0)&=(0,0,1),& \mathbf r(2,0)&=(2,0,5),\\ \mathbf r(0,1)&=(0,1,0),& \mathbf r(2,1)&=(2,1,4). \end{align*} These four points bound the parallelogram patch.

Verification The normal βŸ¨βˆ’2,1,1⟩\langle-2,1,1\rangle is perpendicular to both tangent vectors, and each corner satisfies z=1+2xβˆ’yz=1+2x-y.

Original worksheet page 2: question and worked solution for 6-2-001

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