Parametric Surfaces — Question 9

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Question 9

Let 𝒓(u,v)=⟨ucos⁡v,usin⁡v,u2⟩,1≤u≤2,0≤v≤π.\mathbf r(u,v)=\langle u\cos v,u\sin v,u^2\rangle, \qquad 1\le u\le 2,\qquad 0\le v\le\pi. Describe all boundary curves of the surface patch.

Tasks

  1. Find the curves corresponding to u=1u=1 and u=2u=2.

  2. Find the curves corresponding to v=0v=0 and v=πv=\pi.

  3. Identify the surface and verify that the four curves join correctly.

Original worksheet page 1: question and worked solution for 6-2-009
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Question 9 – Solution

Strategy. Each edge of the rectangular parameter domain maps to one boundary curve.

Step 1: Constant-uu edges u=1:⟨cos⁡v,sin⁡v,1⟩,u=2:⟨2cos⁡v,2sin⁡v,4⟩,0≤v≤π.u=1:\ \langle\cos v,\sin v,1\rangle, \qquad u=2:\ \langle 2\cos v,2\sin v,4\rangle, \quad 0\le v\le\pi. These are semicircles at heights 11 and 44.

Step 2: Constant-vv edges v=0:⟨u,0,u2⟩,v=π:⟨−u,0,u2⟩,1≤u≤2.v=0:\ \langle u,0,u^2\rangle, \qquad v=\pi:\ \langle-u,0,u^2\rangle, \quad 1\le u\le 2. These are parabolic side curves in the plane y=0y=0.

See the diagram in the original worksheet below.

Step 3: Identify and join Since x2+y2=u2x^2+y^2=u^2 and z=u2z=u^2, the patch lies on z=x2+y2z=x^2+y^2 above the half-annulus 1≤x2+y2≤41\le x^2+y^2\le 4, y≥0y\ge 0.

Verification The four corner images are (1,0,1)(1,0,1), (−1,0,1)(-1,0,1), (2,0,4)(2,0,4), and (−2,0,4)(-2,0,4); each occurs as an endpoint of exactly two adjacent boundary curves.

Original worksheet page 2: question and worked solution for 6-2-009

Original worksheet layout. Use Enlarge or open the PDF for a closer view.