Periodic Functions & Orthogonal Functions — Question 1

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Question 1

A positive number TT is a period of ff if f(x+T)=f(x)f(x+T)=f(x) for every real xx. A fundamental period is the smallest positive period, when one exists. Consider f(x)=sin⁡6x+cos⁡10x.f(x)=\sin 6x+\cos 10x. You may use linear independence of sines and cosines at distinct positive integer frequencies; justify that fact here by integrating products on [0,2π][0,2\pi].

Tasks

  1. Find a common period of the two summands. Explain why a common period alone does not prove that the sum has that fundamental period.

  2. Expand f(x+T)−f(x)f(x+T)-f(x) and use independence to characterize every positive period of ff. Determine the fundamental period exactly.

  3. Find the fundamental period of g(x)=3f(2x−1)+7g(x)=3f(2x-1)+7. Explain the effects of translation, nonzero amplitude scaling and a constant offset.

  4. Decide whether a nonzero constant function and the zero function have fundamental periods. Explain why the definition cannot simply assign either function period zero as a fundamental period.

Original worksheet page 1: question and worked solution for 8-3-001
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Question 1 – Solution

Strategy. Prove that a period of the sum must preserve each of its distinct frequency components.

Step 1: Find a candidate period. The summands have periods π/3\pi/3 and π/5\pi/5, and π\pi is a common period. Thus π\pi is a period of ff. In general, cancellation can give a sum a shorter period or even make it constant, so minimality still needs proof.

Step 2: Prove necessity and minimality. Product-to-sum identities show that distinct positive-integer sine/cosine frequencies have zero product integral on [0,2π][0,2\pi], while each squared integral equals π\pi. Multiplying a zero linear combination by each component and integrating therefore forces every coefficient to vanish. Expanding the shift of ff now gives cos⁡6T=1,sin⁡6T=0,cos⁡10T=1,sin⁡10T=0.\cos 6T=1,\quad\sin 6T=0,\quad\cos 10T=1,\quad\sin 10T=0. Equivalently, 6T=2πm6T=2\pi m and 10T=2πn10T=2\pi n for integers m,nm,n. Then 5m=3n5m=3n, so m=3j,n=5jm=3j,n=5j and T=jπT=j\pi. Conversely every such positive shift works. Hence Positive periods: jπ(j=1,2,…),T0=π.\boxed{\text{Positive periods: }j\pi\ (j=1,2,\ldots),\qquad T_0=\pi.}

Step 3: Transform the independent variable. Since 2x−12x-1 ranges over all real numbers, a shift T>0T>0 preserves gg exactly when 2T2T preserves ff. Thus Tg=π/2\boxed{T_g=\pi/2}. Translation, multiplication by a nonzero constant and addition of a constant do not change the set of periods; the argument dilation rescales it.

Step 4: Treat constant functions separately. Every positive number is a period of a constant function, including the zero function. There is no smallest positive number, so neither has a fundamental period. Zero is excluded by the definition and cannot be used to repair this lack of a least positive period.

Original worksheet page 2: question and worked solution for 8-3-001

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