Question 3
Let solve on , , where . For this problem, initial data are prescribed at ; spatial boundary data are prescribed at . The outward normal derivative is , with on the left and on the right. Consider Dirichlet data prescribe , Neumann data prescribe , and Robin data prescribe a linear combination with nonzero coefficients of both.
Tasks
Classify each condition, and identify the portions of the space–time rectangle on which they are prescribed. Is a spatial boundary?
Rewrite the right condition with . Write the corresponding coordinate form of if it were imposed at the left endpoint instead.
Classify the spatial boundary operator when , and decide exactly when the displayed spatial data are homogeneous. Distinguish this from homogeneity of the PDE and of the initial data.
Verify the manufactured field . Find that make it solve the full displayed problem, and illustrate where each datum acts.
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Question 3 – Solution
Strategy. Identify both the operator being prescribed and the geometric location of the data.
Step 1: Locate and name the data. The bottom edge carries initial displacement/temperature data . The left edge carries Dirichlet data ; the right carries Robin data . The top is a final-time slice, not a spatial boundary. No data are prescribed there in this initial-boundary-value problem.
Step 2: Keep the outward signs. At the right, the condition is . At the left, the analogous outward-normal condition would be . Changing the endpoint changes the sign of the normal derivative, not the sign of the prescribed value by convention.
Step 3: Classify homogeneity at each level. When , the right condition is Neumann, since . The spatial data are homogeneous exactly when and . The PDE is already linear homogeneous; initial data are homogeneous exactly when . These are three separate assertions. A nonzero Robin coefficient does not itself make the condition nonhomogeneous.
Step 4: Verify all parts of a full problem. Here and , so the PDE holds. Evaluation gives These data also agree at their shared corners. The diagram locates the data; it is a space–time domain, not a graph of the solution value.
See the diagram in the original worksheet below.