Separation of Variables — Question 1

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Question 1

Let I,JI,J be open intervals, κ>0\kappa>0, r∈ℝr\in\mathbb R, and consider ut=κuxx+ru((x,t)∈I×J).u_t=\kappa u_{xx}+ru\qquad ((x,t)\in I\times J). A separated field is u(x,t)=X(x)T(t)u(x,t)=X(x)T(t), with X∈C2(I)X\in C^2(I) and T∈C1(J)T\in C^1(J). Assume neither factor is identically zero. Do not assume either factor is nonzero at every point.

Tasks

  1. Substitute the product into the PDE. Choose one time where TT is nonzero and use it to derive a spatial ODE on all of II, without dividing by XX.

  2. Show that a single real constant λ\lambda gives X″+λX=0X''+\lambda X=0 and T′=(r−κλ)TT'=(r-\kappa\lambda)T everywhere on their respective intervals. Prove the converse as well.

  3. Determine whether a nontrivial TT can vanish at a time in JJ. Explain why zeros of XX do not invalidate the separated field and what happens if a factor is identically zero.

  4. Verify X(x)=sin⁡(2x)X(x)=\sin(2x) when I=ℝI=\mathbb R. Find all corresponding time factors, determine the growth threshold in rr, and explain the harmless freedom to rescale the two factors reciprocally.

Original worksheet page 1: question and worked solution for 9-4-001
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Question 1 – Solution

Strategy. Evaluate at a nonzero anchor value of one factor before deriving equations valid even at zeros of the other.

Step 1: Derive a global spatial identity. Substitution yields XT′=κX″T+rXTXT'=\kappa X''T+rXT. Choose t0∈Jt_0\in J with T(t0)≠0T(t_0)\ne 0. Evaluating there gives, for every x∈Ix\in I, κX″(x)=(T′(t0)T(t0)−r)X(x).\kappa X''(x)=\left(\frac{T'(t_0)}{T(t_0)}-r\right)X(x). Set λ=(r−T′(t0)/T(t0))/κ\lambda=(r-T'(t_0)/T(t_0))/\kappa. Then X″+λX=0\boxed{X''+\lambda X=0} on all of II, including any zeros of XX.

Step 2: Recover the time equation and the converse. Substituting X″=−λXX''=-\lambda X into the product identity gives X[T′−(r−κλ)T]=0X[T'-(r-\kappa\lambda)T]=0. Choose x0x_0 with X(x0)≠0X(x_0)\ne 0 to obtain T′=(r−κλ)Ton J.\boxed{T'=(r-\kappa\lambda)T\quad\text{on }J.} The constant is independent of both variables; a different anchor must give the same value because XX is not identically zero. Conversely, these two ODEs imply the original product identity directly, without any divisions. Thus every such pair of factors produces a PDE solution.

Step 3: Treat zeros and the excluded trivial field. The time equation gives T(t)=Ce(r−κλ)(t−t0)T(t)=C e^{(r-\kappa\lambda)(t-t_0)}. For a nontrivial factor C≠0C\ne 0, it never vanishes. Spatial zeros are allowed; the identities above remain valid there. A factor identically zero produces u≡0u\equiv 0, which solves the PDE but determines no separation constant from its chosen factors. The trivial field must be retained separately, not mistakenly assigned restrictions obtained by division.

Step 4: Verify a concrete mode and its normalization. For X=sin⁡(2x)X=\sin(2x), X″=−4XX''=-4X, so λ=4\lambda=4 and u(x,t)=Csin⁡(2x)e(r−4κ)t.u(x,t)=C\sin(2x)e^{(r-4\kappa)t}. Its nonzero amplitude grows if r>4κr>4\kappa, is constant if r=4κr=4\kappa, and decays if r<4κr<4\kappa. Direct differentiation verifies the PDE, including at x=nπ/2x=n\pi/2. Replacing (X,T)(X,T) by (aX,T/a)(aX,T/a) for a≠0a\ne 0 leaves uu unchanged; the two factors are not individually unique until a normalization is chosen.

Original worksheet page 2: question and worked solution for 9-4-001

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