Differentiation Formulas — Question 4

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Question 4

Let f(x)=arctan⁡x1+x2+x5ex.f(x)=\frac{\arctan x}{1+x^2}+x^5e^x.

  • (a) Compute f′(x)f'(x).

  • (b) Write the equation for critical numbers and approximate one in (−5,−4)(-5,-4) to six decimal places.

Original worksheet page 1: question and worked solution for 3-3-004
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Question 4 - Solution

(a) Differentiate

The quotient and product rules give

f′(x)=1−2xarctan⁡x(1+x2)2+exx4(x+5).\boxed{f'(x)=\frac{1-2x\arctan x}{(1+x^2)^2}+e^x x^4(x+5).}

(b) Critical numbers

The derivative exists for every real xx, since 1+x2>01+x^2>0.

Thus critical numbers solve f′(x)=0f'(x)=0. Bisection on (−5,−4)(-5,-4) gives

x≈−4.995520.\boxed{x\approx -4.995520.}

The derivative has opposite signs at the ends of this interval, so continuity guarantees a root there.

Original worksheet page 2: question and worked solution for 3-3-004

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