Alternating Series Test — Question 7

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Question 7

Consider ∑n=1∞(−1)ne−n\displaystyle\sum_{n=1}^{\infty}(-1)^ne^{-n}.

  1. Verify the AST hypotheses.

  2. Test absolute convergence using a geometric series.

  3. Find the exact sum and classify convergence.

Original worksheet page 1: question and worked solution for 4-8-007
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Question 7 – Solution

Step 1: Verify the AST.

With bn=e−n>0b_n=e^{-n}>0, we have bn+1=e−1bn<bnb_{n+1}=e^{-1}b_n<b_n and bn→0b_n\to0. Thus the series converges.

Step 2: Test absolute convergence.

∑|(−1)ne−n|=∑(e−1)n,\sum|(-1)^ne^{-n}|=\sum(e^{-1})^n, a geometric series with ratio e−1<1e^{-1}<1. Hence convergence is absolute.

Step 3: Find the sum.

The original series is geometric with first term −e−1-e^{-1} and ratio −e−1-e^{-1}: S=−e−11+e−1=−1e+1.S=\frac{-e^{-1}}{1+e^{-1}}=-\frac1{e+1}.

Original worksheet page 2: question and worked solution for 4-8-007

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