Vector Functions — Question 6

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Question 6

Find constants a,b,ca,b,c so that limt→0⟨1+at−1t,sin⁡(bt)t,ect−1t⟩=⟨2,3,−4⟩.\lim_{t\to 0}\left\langle\frac{\sqrt{1+at}-1}{t},\ \frac{\sin(bt)}t,\ \frac{e^{ct}-1}{t}\right\rangle=\left\langle 2,3,-4\right\rangle. Justify the limit component by component.

Original worksheet page 1: question and worked solution for 6-6-006
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Question 6 – Solution

Strategy A vector limit equals the target precisely when all component limits equal their corresponding target components.

See the diagram in the original worksheet below.

First component Rationalizing gives 1+at−1t=a1+at+1→a2,\frac{\sqrt{1+at}-1}{t}=\frac{a}{\sqrt{1+at}+1}\longrightarrow\frac a2, so a=4a=4.

Other components Standard limits give sin⁡(bt)/t→b\sin(bt)/t\to b and (ect−1)/t→c(e^{ct}-1)/t\to c. Hence a=4,b=3,c=−4\boxed{a=4,\ b=3,\ c=-4}.

Verification The three component limits are respectively 2,3,−42,3,-4.

Original worksheet page 2: question and worked solution for 6-6-006

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