Line Integrals of Vector Fields β€” Question 1

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Question 1

Let 𝑭(x,y)=⟨y,x2⟩,𝒓(t)=⟨t,t2⟩,0≀t≀1.\mathbf F(x,y)=\langle y,x^2\rangle,\qquad \mathbf r(t)=\langle t,t^2\rangle,\quad 0\le t\le 1. Evaluate the line integral ∫C𝑭⋅d𝒓\displaystyle\int_C\mathbf F\cdot d\mathbf r.

Tasks

  1. Evaluate 𝑭\mathbf F along the curve and compute 𝒓′(t)\mathbf r'(t).

  2. Form the dot product and evaluate the integral.

  3. State how the sign of the integrand agrees with the geometry.

Original worksheet page 1: question and worked solution for 5-4-001
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Question 1 – Solution

Strategy. Use ∫C𝑭⋅d𝒓=∫ab𝑭(𝒓(t))⋅𝒓′(t)dt\int_C\mathbf F\cdot d\mathbf r=\int_a^b\mathbf F(\mathbf r(t))\cdot\mathbf r'(t)\,dt.

Step 1: Restrict the field to the curve Since x=tx=t and y=t2y=t^2, 𝑭(𝒓(t))=⟨t2,t2⟩,𝒓′(t)=⟨1,2t⟩.\mathbf F(\mathbf r(t))=\langle t^2,t^2\rangle,\qquad \mathbf r'(t)=\langle 1,2t\rangle.

See the diagram in the original worksheet below.

Step 2: Form the scalar integrand 𝑭(𝒓(t))⋅𝒓′(t)=t2+2t3.\mathbf F(\mathbf r(t))\cdot\mathbf r'(t)=t^2+2t^3. Therefore ∫C𝑭⋅d𝒓=∫01(t2+2t3)dt=[t33+t42]01=56.\int_C\mathbf F\cdot d\mathbf r =\int_0^1(t^2+2t^3)\,dt =\left[\frac{t^3}{3}+\frac{t^4}{2}\right]_0^1 =\boxed{\frac 56}.

Verification For 0≀t≀10\le t\le 1, both components of the field and both components of the velocity are nonnegative. Their dot product must be nonnegative, consistent with the positive answer.

Original worksheet page 2: question and worked solution for 5-4-001

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